11-20.7z Direct

import subprocess import os filename = "11-20.7z" while True: # Attempt to extract. -p can be used if there's a known password. result = subprocess.run(["7z", "x", filename, "-y"], capture_output=True) # Logic to find the next .7z file in the directory next_files = [f for f in os.listdir('.') if f.endswith('.7z') and f != filename] if not next_files: break filename = next_files[0] print(f"Extracted: filename") Use code with caution. Copied to clipboard

The first step is always to identify what you are dealing with. Using the file command in Linux or a hex editor like 010 Editor helps verify the file header. : file 11-20.7z 11-20.7z

The flag usually follows a specific format, such as CTF... or flag... . : CTFn3st3d_z1ps_4r3_fun_12345 import subprocess import os filename = "11-20